(2y^2-y+6)-2(y^2-3y+5)=11

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Solution for (2y^2-y+6)-2(y^2-3y+5)=11 equation: 



(2y^2-y+6)-2(y^2-3y+5)=11

We move all terms to the left:

(2y^2-y+6)-2(y^2-3y+5)-(11)=0

We multiply parentheses

-2y^2+(2y^2-y+6)+6y-10-11=0

We get rid of parentheses

-2y^2+2y^2-y+6y+6-10-11=0

We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3

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